document.write( "Question 530769: The perimeter of a rectangle is 68cm. If the diagonal is 26cm, find the dimensions of the rectangle. \n" ); document.write( "
Algebra.Com's Answer #350210 by oberobic(2304)![]() ![]() ![]() You can put this solution on YOUR website! perimeter = 2(a +b), where a = length and b = width \n" ); document.write( "p = 68 \n" ); document.write( "a+b = 34 \n" ); document.write( "so \n" ); document.write( "a = 34-b \n" ); document.write( ". \n" ); document.write( "diagonal = c = 26 cm \n" ); document.write( ". \n" ); document.write( "Pythagorean Theorem teaches us that: \n" ); document.write( ". \n" ); document.write( "c^2 = a^2 + b^2 \n" ); document.write( ". \n" ); document.write( "Substitute for a = 34-b and c = 26 \n" ); document.write( ". \n" ); document.write( "26^2 = (34-b)^2 + b^2 \n" ); document.write( ", \n" ); document.write( "Collect terms. \n" ); document.write( ". \n" ); document.write( "676 = (b^2 -68b + 1156) + b^2 \n" ); document.write( ". \n" ); document.write( "2b^2 -68b + 480 = 0 \n" ); document.write( ". \n" ); document.write( "b^2 -34b +240 = 0 \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Factor \n" ); document.write( ". \n" ); document.write( "(b-10)(b-24) = 0 \n" ); document.write( ". \n" ); document.write( "b = 10 or 24 \n" ); document.write( "a = 34 -b \n" ); document.write( "so \n" ); document.write( "a = 24 or 10 respectively \n" ); document.write( ". \n" ); document.write( "Either way, the two sides of the rectangle are 10 and 24. \n" ); document.write( ". \n" ); document.write( "Checking, we find: \n" ); document.write( "10^2 + 24^2 = 26^2 \n" ); document.write( "100 + 576 = 676 \n" ); document.write( "True \n" ); document.write( ". \n" ); document.write( "Answer: The rectangle has dimensions of 10 by 24 cm. \n" ); document.write( ". \n" ); document.write( "Done. \n" ); document.write( " |