document.write( "Question 530769: The perimeter of a rectangle is 68cm. If the diagonal is 26cm, find the dimensions of the rectangle. \n" ); document.write( "
Algebra.Com's Answer #350210 by oberobic(2304)\"\" \"About 
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perimeter = 2(a +b), where a = length and b = width
\n" ); document.write( "p = 68
\n" ); document.write( "a+b = 34
\n" ); document.write( "so
\n" ); document.write( "a = 34-b
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\n" ); document.write( "diagonal = c = 26 cm
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\n" ); document.write( "Pythagorean Theorem teaches us that:
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\n" ); document.write( "c^2 = a^2 + b^2
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\n" ); document.write( "Substitute for a = 34-b and c = 26
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\n" ); document.write( "26^2 = (34-b)^2 + b^2
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\n" ); document.write( "Collect terms.
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\n" ); document.write( "676 = (b^2 -68b + 1156) + b^2
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\n" ); document.write( "2b^2 -68b + 480 = 0
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\n" ); document.write( "b^2 -34b +240 = 0
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\n" ); document.write( "\"+graph%28500%2C500%2C-20%2C40%2C-60%2C40%2Cx%5E2-34%2Ax%2B240%29+\"
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\n" ); document.write( "Factor
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\n" ); document.write( "(b-10)(b-24) = 0
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\n" ); document.write( "b = 10 or 24
\n" ); document.write( "a = 34 -b
\n" ); document.write( "so
\n" ); document.write( "a = 24 or 10 respectively
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\n" ); document.write( "Either way, the two sides of the rectangle are 10 and 24.
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\n" ); document.write( "Checking, we find:
\n" ); document.write( "10^2 + 24^2 = 26^2
\n" ); document.write( "100 + 576 = 676
\n" ); document.write( "True
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\n" ); document.write( "Answer: The rectangle has dimensions of 10 by 24 cm.
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\n" ); document.write( "Done.
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