document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=530789>Question 530789</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How many quarts of pure (100%) antifreeze and a 50% antifreeze and 50% water mix should be combined to make 14 quarts of 70% antifreeze and 30% water? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #350209 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=350209\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x=amount of pure antifreeze needed<BR>\n" );
document.write( "Then 14-x=amount of 50% antifreeze needed\r<BR>\n" );
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document.write( "Now we know that the amount of pure antifreeze that exists before the mixture takes place has to equal the amount of pure antifreeze that exists after the mixture takes place, sooooo:<BR>\n" );
document.write( "x+0.50(14-x)=0.70*14<BR>\n" );
document.write( "x+7-0.50x=9.8 simplify<BR>\n" );
document.write( "0.50x=2.8<BR>\n" );
document.write( "x=5.6 quarts----amount of pure antifreeze needed\r<BR>\n" );
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document.write( "CK<BR>\n" );
document.write( "5.6+0.50*8.4=0.70*14<BR>\n" );
document.write( "5.6+4.2=9.8<BR>\n" );
document.write( "9.8=9.8\r<BR>\n" );
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document.write( "Hope this helps----ptaylor<BR>\n" );
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