document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=530653>Question 530653</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how to factor 3x^2-22x+40 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #350181 by </B><A HREF=/tutors/aboutme.mpl?userid=algebrahouse.com><B>algebrahouse.com(1659)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=algebrahouse.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=algebrahouse.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=350181\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3x² - 22x + 40<BR>\n" );
document.write( "= 3x² - 12x - 10x + 40 {factoring by grouping, split -22x into -12x and -10x}<BR>\n" );
document.write( "= 3x(x - 4) - 10(x - 4) {factored 3x out of 1st two terms and -10 out of last two}<BR>\n" );
document.write( "= (3x - 10)(x - 4) {factored x - 4 out of the two terms}<BR>\n" );
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