document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=530639>Question 530639</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how long is the hypotenuse of a 30-60-90 triangle .if the shorter leg measures 10 cm ?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #350174 by </B><A HREF=/tutors/aboutme.mpl?userid=oberobic><B>oberobic(2304)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=oberobic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=350174\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The ratio of the sides of a 30-60-90 triangle are known to be 1:2:sqrt(3).<BR>\n" );
document.write( "The shorter leg is 10 cm.<BR>\n" );
document.write( "Therefore, the hypotenuse is 2*10 = 20 cm.<BR>\n" );
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document.write( "Check the solution with the Pythagorean Theorem.<BR>\n" );
document.write( "c^2 = a^2 + b^2<BR>\n" );
document.write( "20^2 = 10^2 + (10*sqrt(3))^2<BR>\n" );
document.write( "400 = 400<BR>\n" );
document.write( "True.<BR>\n" );
document.write( ".<BR>\n" );
document.write( "The hypotenuse of the triangle is 20 cm.<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Done. </SPAN>\n" );
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