document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=52318>Question 52318</A>: <I><SPAN STYLE=\"word-break: break-all;\"> One number is 5 greater than a second number.  If the lesser number is subtracted from 3 times the greater number, the difference is 9.  Find the numbers. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #35017 by </B><A HREF=/tutors/aboutme.mpl?userid=darq><B>darq(90)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=darq><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=darq><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=35017\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> One number is 5 greater than a second number.  If the lesser number is subtracted from 3 times the greater number, the difference is 9.  Find the numbers.\r<BR>\n" );
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document.write( "first number=x<BR>\n" );
document.write( "second number=x+5\r<BR>\n" );
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document.write( "3*(x+5)-x=9<BR>\n" );
document.write( "3x+15-x=9<BR>\n" );
document.write( "2x=-6<BR>\n" );
document.write( "x=-3\r<BR>\n" );
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document.write( "first number=-3<BR>\n" );
document.write( "second number=2 </SPAN>\n" );
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