document.write( "Question 530563: Rewrite the expression\r
\n" ); document.write( "\n" ); document.write( "ln5 + 5lnx + 2ln(x^2+6)\r
\n" ); document.write( "\n" ); document.write( "as a single logarithm lnA. Then the function A= \r
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Algebra.Com's Answer #350164 by reviewermath(1029)\"\" \"About 
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= \"++ln5+%2B+ln%28x%5E5%29+%2B+ln%28x%5E2%2B6%29%5E2\"
\n" ); document.write( " = \"ln5%28x%5E5%29%28x%5E2%2B6%29%5E2\"
\n" ); document.write( "Therefore \"A+=+5%28x%5E5%29%28x%5E2%2B6%29%5E2\"
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