document.write( "Question 530521: Find three consecutive odd intergers such that the sum of all three is 36 less than the product of the smaller two. Show the equation and all the steps. \n" ); document.write( "

Algebra.Com's Answer #350153 by oberobic(2304) $\"\"$ $\"About$

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Three consecutive odd integers can be defined as:
\n" ); document.write( "x
\n" ); document.write( "x+2
\n" ); document.write( "x+4
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\n" ); document.write( "The sum of these three number is 36 less than the product of the smaller two.
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\n" ); document.write( "x +x+2 +x+4 +36 = x*(x+2)
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\n" ); document.write( "Solve
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\n" ); document.write( "3x + 42 = x^2 + 2x
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\n" ); document.write( "x^2 -x -42 = 0
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\n" ); document.write( "Factor
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\n" ); document.write( "(x-7)(x+6) = 0
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\n" ); document.write( "x = 7 or -6
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\n" ); document.write( "-6 is not odd, so we select 7 as the answer.
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\n" ); document.write( "x = 7
\n" ); document.write( "x+2 = 9
\n" ); document.write( "x+4 = 11
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\n" ); document.write( "Check the values.
\n" ); document.write( "7*9 = 63
\n" ); document.write( "7+9+11 = 27
\n" ); document.write( "27+36 = 63
\n" ); document.write( "Correct
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\n" ); document.write( "Answer: The numbers are 7, 9, and 11.
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\n" ); document.write( "Done. \n" ); document.write( "

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