document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=530557>Question 530557</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two cars leave delhi at the same time ,travelling in opposite directions.if the average speed of one car is 5km/hr more than that of the other and they are 425 km apart at the end of 5hrs,what is the average speed oe each? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #350151 by </B><A HREF=/tutors/aboutme.mpl?userid=oberobic><B>oberobic(2304)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=oberobic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=350151\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The two cars are moving in opposite directions, so they are separating at the sum of their speeds.<BR>\n" );
document.write( "Looking at the fundamental distance equation, d = rt, we know:<BR>\n" );
document.write( "d = 425 km<BR>\n" );
document.write( "t = 5 hr<BR>\n" );
document.write( "So, the combined rate = 425/5 = 85 km/hr<BR>\n" );
document.write( "One car goes 5 km/hr faster than the other, which means we can define their speeds as x and x+5.<BR>\n" );
document.write( "x + x+5 = 85<BR>\n" );
document.write( "2x +5 = 85<BR>\n" );
document.write( "2x = 80<BR>\n" );
document.write( "x = 40, which is the speed of one car<BR>\n" );
document.write( "x+5 = 45, which is the speed of the other car<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );