document.write( "Question 530503: I need to know how to find a line perpendicular to y=3x+6 \n" ); document.write( "
Algebra.Com's Answer #350143 by mananth(16946)\"\" \"About 
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1 y = 3 x + 6
\n" ); document.write( "Divide by 1
\n" ); document.write( " y = 3 x + 6
\n" ); document.write( "Compare this equation with y=mx+b
\n" ); document.write( "slope m = 3.00
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\n" ); document.write( "The slope of a line perpendicular to the above line will be the negative reciprocal -0.33
\n" ); document.write( "m1*m2=-1
\n" ); document.write( "The slope of the required line will be - 1/3 \r
\n" ); document.write( "\n" ); document.write( "You need to know the point the line passes through.\r
\n" ); document.write( "\n" ); document.write( "plug slope and the point in the equation y= mx+b
\n" ); document.write( "Find b\r
\n" ); document.write( "\n" ); document.write( "plug slope and b in y= mx+b\r
\n" ); document.write( "\n" ); document.write( "m.ananth@hotmail.ca
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