document.write( "Question 530536: The length of a rectangle is 3 ft more than twice its width, and the area of the rectangle is 35 ft^2 . Find the dimensions of the rectangle. \n" ); document.write( "
Algebra.Com's Answer #350111 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! The length of a rectangle is 3 ft more than twice its width, and the area of the rectangle is 35 ft^2 . Find the dimensions of the rectangle. \n" ); document.write( "--------- \n" ); document.write( "Let width be \"x\" \n" ); document.write( "The length is \"x+3\" \n" ); document.write( "---- \n" ); document.write( "Equation: \n" ); document.write( "area = length*width \n" ); document.write( "35 = (x+3)x \n" ); document.write( "x^2+3x-35 = 0 \n" ); document.write( "x = 4.6 (width) \n" ); document.write( "x+3 = 7.6 (length) \n" ); document.write( "====================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "============ \n" ); document.write( " |