document.write( "Question 530536: The length of a rectangle is 3 ft more than twice its width, and the area of the rectangle is 35 ft^2 . Find the dimensions of the rectangle. \n" ); document.write( "
Algebra.Com's Answer #350111 by stanbon(75887)\"\" \"About 
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The length of a rectangle is 3 ft more than twice its width, and the area of the rectangle is 35 ft^2 . Find the dimensions of the rectangle.
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\n" ); document.write( "Let width be \"x\"
\n" ); document.write( "The length is \"x+3\"
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\n" ); document.write( "Equation:
\n" ); document.write( "area = length*width
\n" ); document.write( "35 = (x+3)x
\n" ); document.write( "x^2+3x-35 = 0
\n" ); document.write( "x = 4.6 (width)
\n" ); document.write( "x+3 = 7.6 (length)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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