document.write( "Question 530447: oe has a collection of nickels and dimes that is worth $7.65. If the number of dimes was doubled and the number of nickels was increased by 35, the value of the coins would be $14.30. How many nickels and dimes does he have? \n" ); document.write( "
Algebra.Com's Answer #350105 by MathTherapy(10858)\"\" \"About 
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\n" ); document.write( "Joe has a collection of nickels and dimes that is worth $7.65. If the number of dimes was doubled and the number of nickels was increased by 35, the value of the coins would be $14.30. How many nickels and dimes does he have?\r
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\n" ); document.write( "\n" ); document.write( "Let amount of dimes be D, and amount of nickels, N\r
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\n" ); document.write( "\n" ); document.write( "Then: . 1(D) + .05(N) = 7.65 ------ 10D + 5N = 765 ----- Multiplying by 100 to clear decimals ----- eq (i)\r
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\n" ); document.write( "\n" ); document.write( "Also, .1(2D) + .05(N + 35) = 14.3 ----- .2D + .05N + 1.75 = 14.3 ------- .2D + .05N = 12.55 ------- 20D + 5N = 1,255 ----- Multiplying by 100 to clear decimals ----- eq (ii)\r
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\n" ); document.write( "\n" ); document.write( "10D + 5N = 765 ------- eq (i)
\n" ); document.write( "20D + 5N = 1,255 ----- eq (ii)
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\n" ); document.write( "- 10D = - 490 ----- Subtracting eq (ii) from (i)\r
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\n" ); document.write( "\n" ); document.write( "D, or amount of dimes = \"%28-+490%29%2F-+10\", or \"490%2F10\", or \"highlight_green%2849%29\"\r
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\n" ); document.write( "\n" ); document.write( "10(49) + 5N = 765 ------- Substituting 49 for D in eq (i)
\n" ); document.write( "490 + 5N = 765
\n" ); document.write( "5N = 765 – 490
\n" ); document.write( "5N = 275\r
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\n" ); document.write( "\n" ); document.write( "N, or amount of nickels = \"275%2F5\", or \"highlight_green%2855%29\"\r
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\n" ); document.write( "\n" ); document.write( "I'll leave the check up to you to perform.\r
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\n" ); document.write( "\n" ); document.write( "Send comments and “thank-yous” to “D” at MathMadEzy@aol.com
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