document.write( "Question 530501: Out of 100 students, (49 girls, 51 boys) if three children are selected what is the probability that at least one is a girl?
\n" ); document.write( "I am missing a key point to this equation because I keep getting 49/97 which I believe is wrong
\n" ); document.write( "Thanks for any help
\n" ); document.write( "

Algebra.Com's Answer #350103 by oberobic(2304)\"\" \"About 
You can put this solution on YOUR website!
The probability of picking a girl on the first pick is: 49/100.
\n" ); document.write( ".
\n" ); document.write( "The probability of picking a girl on the second pick depends on whether a girl was picked first.
\n" ); document.write( "If a girl was picked initially, then the probability of picking a girl on the second pick is : 48/99.
\n" ); document.write( "If a boy was picked initially, then the probability of picking a girl on the second pick is: 49/99.
\n" ); document.write( ".
\n" ); document.write( "The probability of picking a girl first and second is: 49/100 * 48/99.
\n" ); document.write( ".
\n" ); document.write( "And so forth.
\n" ); document.write( ".
\n" ); document.write( "You need to determine the conditional probabilities to find the chance of picking at least 1 girl.
\n" ); document.write( ".
\n" ); document.write( "\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "\n" ); document.write( "
1st Pick     \r\n" ); document.write( "2nd Pick     \r\n" ); document.write( "3rd Pick         Probability            \r\n" ); document.write( "Description          \r\n" ); document.write( "
P(girl)=49/100     \r\n" ); document.write( "P(girl)=48/99     \r\n" ); document.write( "P(girl)=47/98     \r\n" ); document.write( "P=0.113939394\r\n" ); document.write( "(A) 3 girls\r\n" ); document.write( "
\"\r\n" ); document.write( "\" \r\n" ); document.write( "P(boy)=51/98\r\n" ); document.write( "P=0.123636364\r\n" ); document.write( "(B) 2 girls, 1 boy\r\n" ); document.write( "
\"\r\n" ); document.write( "P(boy)=51/99\r\n" ); document.write( "P(girl)=48/98\r\n" ); document.write( "P=0.123636364\r\n" ); document.write( "(C) 2 girls, 1 boy\r\n" ); document.write( "
\"\r\n" ); document.write( "\"\r\n" ); document.write( "P(boy)=50/98\r\n" ); document.write( "P=0.128787879\r\n" ); document.write( "(D) 1 girl, 2 boys\r\n" ); document.write( "
P(boy)=51/100\r\n" ); document.write( "P(girl)=49/99\r\n" ); document.write( "P(girl)=48/98\r\n" ); document.write( "P=0.123636364\r\n" ); document.write( "(E) 2 girls, 1 boy\r\n" ); document.write( "
\"\r\n" ); document.write( "\"\r\n" ); document.write( "P(boy)=50/98\r\n" ); document.write( "P=0.128787879\r\n" ); document.write( "(F) 1 girl, 2 boys
\"\r\n" ); document.write( "P(boy)=50/99\r\n" ); document.write( "P(girl)=49/98\r\n" ); document.write( "P=0.128787879\r\n" ); document.write( "(G) 1 girl, 2 boys\r\n" ); document.write( "
\"\r\n" ); document.write( "\"\r\n" ); document.write( "P(boy)=49/98\r\n" ); document.write( "P=0.128787879\r\n" ); document.write( "(H) 3 boys\r\n" ); document.write( "
\r
\n" ); document.write( "\n" ); document.write( "The total probability = 1.00, as you can see.
\n" ); document.write( ".
\n" ); document.write( "P(at least 1 girl) = A+B+C+D+E+F+G = 0.871212121
\n" ); document.write( ".
\n" ); document.write( "OR
\n" ); document.write( ".
\n" ); document.write( "You could see the problem in terms of the chance of picking 3 boys. If you do not pick 3 boys, then you have to pick at least 1 girl.
\n" ); document.write( ".
\n" ); document.write( "P(picking 3 boys) = 51/100 * 50/99 * 49/98 = 0.128787879
\n" ); document.write( ".
\n" ); document.write( "P(picking at least 1 girl) = 1.0 - 0.128787879 = 0.871212121
\n" ); document.write( ".
\n" ); document.write( "Same answer. Two ways to get there.
\n" ); document.write( ".
\n" ); document.write( "Done.
\n" ); document.write( "
\n" ); document.write( "
\n" );