document.write( "Question 530501: Out of 100 students, (49 girls, 51 boys) if three children are selected what is the probability that at least one is a girl?
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document.write( "I am missing a key point to this equation because I keep getting 49/97 which I believe is wrong
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document.write( "Thanks for any help \n" );
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Algebra.Com's Answer #350103 by oberobic(2304)![]() ![]() ![]() You can put this solution on YOUR website! The probability of picking a girl on the first pick is: 49/100. \n" ); document.write( ". \n" ); document.write( "The probability of picking a girl on the second pick depends on whether a girl was picked first. \n" ); document.write( "If a girl was picked initially, then the probability of picking a girl on the second pick is : 48/99. \n" ); document.write( "If a boy was picked initially, then the probability of picking a girl on the second pick is: 49/99. \n" ); document.write( ". \n" ); document.write( "The probability of picking a girl first and second is: 49/100 * 48/99. \n" ); document.write( ". \n" ); document.write( "And so forth. \n" ); document.write( ". \n" ); document.write( "You need to determine the conditional probabilities to find the chance of picking at least 1 girl. \n" ); document.write( ". \n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "The total probability = 1.00, as you can see. \n" ); document.write( ". \n" ); document.write( "P(at least 1 girl) = A+B+C+D+E+F+G = 0.871212121 \n" ); document.write( ". \n" ); document.write( "OR \n" ); document.write( ". \n" ); document.write( "You could see the problem in terms of the chance of picking 3 boys. If you do not pick 3 boys, then you have to pick at least 1 girl. \n" ); document.write( ". \n" ); document.write( "P(picking 3 boys) = 51/100 * 50/99 * 49/98 = 0.128787879 \n" ); document.write( ". \n" ); document.write( "P(picking at least 1 girl) = 1.0 - 0.128787879 = 0.871212121 \n" ); document.write( ". \n" ); document.write( "Same answer. Two ways to get there. \n" ); document.write( ". \n" ); document.write( "Done. \n" ); document.write( " \n" ); document.write( " |