document.write( "Question 530466: Find the equation of a circle given its center C and one point P.\r
\n" ); document.write( "\n" ); document.write( "C(0,4),P(0,0).\r
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Algebra.Com's Answer #350059 by jim_thompson5910(35256)\"\" \"About 
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\"%28x-h%29%5E2%2B%28y-k%29%5E2=r%5E2\" Start with the general equation of a circle.\r
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\n" ); document.write( "\n" ); document.write( "\"%28x-0%29%5E2%2B%28y-4%29%5E2=r%5E2\" Plug in \"h=0\" and \"k=4\" (since the center is the point (h,k) ).\r
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\n" ); document.write( "\n" ); document.write( "\"%280-0%29%5E2%2B%280-4%29%5E2=r%5E2\" Plug in \"x=0\" and \"y=0\" (this is the point that lies on the circle, which is in the form (x,y) ).\r
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\n" ); document.write( "\n" ); document.write( "\"%280%29%5E2%2B%28-4%29%5E2=r%5E2\" Combine like terms.\r
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\n" ); document.write( "\n" ); document.write( "\"0%2B16=r%5E2\" Square each term.\r
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\n" ); document.write( "\n" ); document.write( "\"16=r%5E2\" Add.\r
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\n" ); document.write( "\n" ); document.write( "So because \"h=0\", \"k=4\", and \"r%5E2=16\", this means that the equation of the circle with center (0,4) that goes through the point (0,0) is \r
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\n" ); document.write( "\n" ); document.write( "\"%28x-0%29%5E2%2B%28y-4%29%5E2=16\".\r
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\n" ); document.write( "\n" ); document.write( "which simplifies to \r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2%2B%28y-4%29%5E2=16\"\r
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\n" ); document.write( "\n" ); document.write( "If you need more help, email me at jim_thompson5910@hotmail.com\r
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