document.write( "Question 530447: oe has a collection of nickels and dimes that is worth $7.65. If the number of dimes was doubled and the number of nickels was increased by 35, the value of the coins would be $14.30. How many nickels and dimes does he have? \n" ); document.write( "
Algebra.Com's Answer #350047 by oberobic(2304)\"\" \"About 
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With coin problems you have to keep track of the count of each coin and the value.
\n" ); document.write( "n = number of nickels
\n" ); document.write( "5n = value of the nickels in cents
\n" ); document.write( "d = number of dimes
\n" ); document.write( "10d = value of the times in cents
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\n" ); document.write( "5n + 10d = 765 cents
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\n" ); document.write( "2(10d) + 5(n+35) = 1430 cents
\n" ); document.write( "20d + 5n + 165 = 1430
\n" ); document.write( "20d + 5n = 1265
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\n" ); document.write( "With two equations and two unknowns, you can solve the system of equations.
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\n" ); document.write( "5n + 10d = 765
\n" ); document.write( "5n + 20d = 1265
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\n" ); document.write( "-10d = -500
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\n" ); document.write( "d = 50
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\n" ); document.write( "Substitute d = 50 to find n.
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\n" ); document.write( "5n + 10d = 765
\n" ); document.write( "5n + 10(50) = 765
\n" ); document.write( "5n = 265
\n" ); document.write( "n = 53
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\n" ); document.write( "Check the values to make sure the above solution is the correct answer.
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\n" ); document.write( "5(53) = 265
\n" ); document.write( "10(50) = 500
\n" ); document.write( "265 + 500 = 765 cents
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\n" ); document.write( "Check the other equation, too.
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\n" ); document.write( "2(10(50)) + 5(53+35) = 1430 ??
\n" ); document.write( "2(500) + 265 + 175 = 1430
\n" ); document.write( "Correct.
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\n" ); document.write( "Answer: Joe has 53 nickels and 50 dimes.
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\n" ); document.write( "Done.
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