document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=530337>Question 530337</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How many gallons of a 60% antifreeze solution must be mixed with 70 gallons of 25% antifreeze to get a mixture that is 50% antifreeze?\r<BR>\n" );
document.write( "\n" );
document.write( "I don't have the first clue on how to figure this out.  Can you please explain this process? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #350007 by </B><A HREF=/tutors/aboutme.mpl?userid=Earlsdon><B>Earlsdon(6294)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Earlsdon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=350007\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x = the required number of gallons of the 60% antifreeze solution.<BR>\n" );
document.write( "You can represent the amount of antifreeze in the solution as follows:<BR>\n" );
document.write( "Change the percentages to their decimal equivalents: 60% = 0.6, 25% = 0.25, and 50% = 0.5<BR>\n" );
document.write( "For example, the amount of antifreeze in 70 gallons of 25% antifreeze solution = 0.25(70) = 17.5 gallons. <BR>\n" );
document.write( "0.6x+0.25(70) = 0.5(70+x) Simplify.<BR>\n" );
document.write( "0.6x+17.5 = 35+0.5x Subtract 0.5x from both sides.<BR>\n" );
document.write( "0.1x+17.5 = 35 Subtract 17.5 from both sides.<BR>\n" );
document.write( "0.1x = 17.5 Divide by 0.1<BR>\n" );
document.write( "x = 175 gallons </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );