document.write( "Question 530315: Hi!\r
\n" ); document.write( "\n" ); document.write( "I'm not really sure I understand this problem and I'm having problems formulating a solution. There's an attempt below which should be correct but I think my method is ambiguous. A better method would be appreciated and any other help too!\r
\n" ); document.write( "\n" ); document.write( "Paul worked 7 more problems than Jean. Together they worked 55 problems. How many did each boy work?\r
\n" ); document.write( "\n" ); document.write( "\"%287+%2B+Jean%29+%2B+Jean+=+55\"
\n" ); document.write( "\"7+%2B+2Jean+=+55\"
\n" ); document.write( "\"2Jean+=+55+-+7\"
\n" ); document.write( "\"2Jean+=+48\"
\n" ); document.write( "\"Jean+=+24\"\r
\n" ); document.write( "\n" ); document.write( "Paul worked 7 more than Jean therefore \"+24+%2B+7+=+31+\" problems for Paul
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Algebra.Com's Answer #350006 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
I can see only one additional step that you might have included!
\n" ); document.write( "Let P = The number of problems Paul worked on.
\n" ); document.write( "Let J = The number of problems Jean worked on.
\n" ); document.write( "1) P = J+7 \"Paul worked 7 more problems than Jean.\"
\n" ); document.write( "2) P+J = 55 \"Together they worked 55 problems.\"
\n" ); document.write( "Substitute the P from equation 1) for the P in equation 2).
\n" ); document.write( "2a) (J+7)+J = 55 Simplify.
\n" ); document.write( "2b) 2J+7 = 55 Subtract 7 from both sides.
\n" ); document.write( "2c) 2J = 48 Divide by 2.
\n" ); document.write( "2d) J = 24 Substitute into equation 1)
\n" ); document.write( "1a) P = 24+7
\n" ); document.write( "1b) P = 31
\n" ); document.write( "Paul worked 31 problems and Jean worked 24 problems.
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