document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=529878>Question 529878</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Sin(A) = -3/5 with A in quadrant III. Find tan (2A). </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #349986 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=349986\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Sin(A) = -3/5 with A in quadrant III. Find tan (2A).<BR>\n" );
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document.write( "You are working with a right triangle in quadrant III where the opposite side=3, and hypotenuse=5. By the Pythagorean Theorem, the adjacent side=4. Tan(A)=-3/4<BR>\n" );
document.write( "Identity:Tan(2A)=2tan(A)/(1-tan^2(A))<BR>\n" );
document.write( "Tan(2A)=2(-3/4)/(1-(-3/4)^2)<BR>\n" );
document.write( "Tan(2A)=-(3/2)/(7/16)=48/14=-24/7 </SPAN>\n" );
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