document.write( "Question 530254: A chemist wants to make a 45% solution of Sulfuric Acid more concentrated by addingpure sulfuric acid. How much pure sulfuric acid must be added to get an 80% solution of sulfuric acid? \n" ); document.write( "
Algebra.Com's Answer #349975 by josmiceli(19441)\"\" \"About 
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Let \"+1+\" = unit of sulfuric acid solution originally
\n" ); document.write( "Let \"+x+\" units of pure sulfuric acid to be added
\n" ); document.write( "given:
\n" ); document.write( "\"+.45+\" = units of sulfuric acid originally
\n" ); document.write( "---------
\n" ); document.write( "\"+%28+.45+%2B+x+%29+%2F+%28+1+%2B+x+%29+=+.8+\"
\n" ); document.write( "\"+.45+%2B+x+=+.8%2A%28+1+%2B+x+%29+\"
\n" ); document.write( "\"+.45+%2B+x+=+.8+%2B+.8x+\"
\n" ); document.write( "\"+.2x+=+.8+-+.45+\"
\n" ); document.write( "\"+.2x+=+.35+\"
\n" ); document.write( "\"+x+=+1.75+\"
\n" ); document.write( "The ratio of pure acid to be added to solution already present
\n" ); document.write( "must be 1.75/1 or 7/4
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