document.write( "Question 52469: Find the domain of the function algebraically:
\n" ); document.write( "f(x) = (x^2+ 4)^1/2 \n" ); document.write( "

Algebra.Com's Answer #34996 by funmath(2933) $\"\"$ $\"About$

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You are probably aware that you can't take the square root of a negative number and get a real number solution. So the domain of even roots can be found by setting the inside of the root>=0.
\n" ); document.write( "x^2+4>=0
\n" ); document.write( "x^2+4-4>=0-4
\n" ); document.write( "x^2>=-4
\n" ); document.write( "sqrt(x^2)>=sqrt(-4)
\n" ); document.write( "Only you can't take the square root of a negative number, so there is no number that x can't be.
\n" ); document.write( "The domain is all real numbers. \n" ); document.write( "

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