document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=530230>Question 530230</A>: <I><SPAN STYLE=\"word-break: break-all;\"> solve by substitution x+2y=8 and x+3y=12 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #349959 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=349959\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Hint: Solve for x in equation 1 to get x = 8-2y\r<BR>\n" );
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document.write( "Now plug in x = 8-2y into x+3y=12 to get 8-2y + 3y = 12\r<BR>\n" );
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document.write( "From here, solve for y. Once you have a value for y, use it to find x. </SPAN>\n" );
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