document.write( "Question 530089: Use the method of substitution to solve the system:(Enter your answer(s) as ordered pair(s). If there is more than one ordered pair, use commas between ordered pairs.)\r
\n" ); document.write( "\n" ); document.write( "xy=2
\n" ); document.write( "5x-y+9=0
\n" ); document.write( "

Algebra.Com's Answer #349950 by ankor@dixie-net.com(22740)\"\" \"About 
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xy = 2
\n" ); document.write( "y = \"2%2Fx\"
\n" ); document.write( "5x - y + 9 = 0
\n" ); document.write( "substitute 2/x for y
\n" ); document.write( "5x - \"2%2Fx\" + 9 = 0
\n" ); document.write( "Mult equation by x
\n" ); document.write( "5x^2 - 2 + 9x = 0
\n" ); document.write( "a quadratic equation
\n" ); document.write( "5x^2 + 9x - 2 = 0
\n" ); document.write( "Factors to
\n" ); document.write( "(5x - 1)(x + 2) = 0
\n" ); document.write( "two solutions
\n" ); document.write( "5x = 1
\n" ); document.write( "x = .2
\n" ); document.write( "and
\n" ); document.write( "x = -2
\n" ); document.write( ":
\n" ); document.write( "Find y when x = .2
\n" ); document.write( ".2y = 2
\n" ); document.write( "y = 2/.2
\n" ); document.write( "y = 10
\n" ); document.write( "Ordered pair, .2, 10
\n" ); document.write( ":
\n" ); document.write( "Find y when x = -2
\n" ); document.write( "-2y = 2
\n" ); document.write( "y = 2/-2
\n" ); document.write( "y = -1
\n" ); document.write( "Ordered pair -2, -1
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