document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=530182>Question 530182</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 2.	Which would be hardest for you to give up: Your computer or your television? In a recent survey of 1677 U.S. Internet users, 74% of the young tech elite (average age of 22) say their computer would be very hard to give up (PC Magazine, February 3, 2004). Only 48% say their television would be very hard to give up.\r<BR>\n" );
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document.write( "a.Develop a 95% confidence interval for the proportion of the young tech elite that would find it very hard to give up their computer. <BR>\n" );
document.write( "b.Develop a 99% confidence interval for the proportion of the young tech elite that would find it very hard to give up their television. <BR>\n" );
document.write( "c.In which case, part (a) or part (b), is the margin of error larger? Explain why.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #349928 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=349928\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Which would be hardest for you to give up: Your computer or your television? <BR>\n" );
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document.write( "In a recent survey of 1677 U.S. Internet users, 74% of the young tech elite (average age of 22) say their computer would be very hard to give up.<BR>\n" );
document.write( "a.Develop a 95% confidence interval for the proportion of the young tech elite that would find it very hard to give up their computer.<BR>\n" );
document.write( "The sample proportion = 0.74<BR>\n" );
document.write( "Margin of Error = 1.96*sqrt{0.74*0.26/1677] = 0.02<BR>\n" );
document.write( "95% CI: 0.74-0.-02 < p < 0.74+0.02 <BR>\n" );
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document.write( "Only 48% say their television would be very hard to give up. <BR>\n" );
document.write( "b.Develop a 99% confidence interval for the proportion of the young tech elite that would find it very hard to give up their television.<BR>\n" );
document.write( "The sample proportion = 0.48<BR>\n" );
document.write( "99% Margin of Error = 2.5758*sqrt[0.48*0.52/1677] = 0.03<BR>\n" );
document.write( "99%CI: 0.48-0.03 < p < 0.48+0.03<BR>\n" );
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document.write( "c.In which case, part (a) or part (b), is the margin of <BR>\n" );
document.write( "error larger? Explain why.<BR>\n" );
document.write( "Ans: b, because the Margin of error is larger.<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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