document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=529905>Question 529905</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hello, \r<BR>\n" );
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document.write( ",y question is below. simple but i am confused about one aspect:\r<BR>\n" );
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document.write( "If a single card is drawn from a standard 52-card deck, what is the probability that it is either a seven or a spade?\r<BR>\n" );
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document.write( "I understand there are 4 sevens in a deck and 13 spades. Together totaling to 16/52 simplified to 4/13. I am confused if I should be counting the 7 of spades twice considering it is both a seven and a spade which would make the answer 17/52. \r<BR>\n" );
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document.write( "thank you for your help, i know it's simple but i hope to receive an answer soon.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #349856 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=349856\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If a single card is drawn from a standard 52-card deck, what is the probability that it is either a seven or a spade? <BR>\n" );
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document.write( "P(7 or spade) = P(7) + P(spade) - P(7 and spade)<BR>\n" );
document.write( "= 4/52 + 13/52 - 1/52 = 16/52 = 4/13<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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