document.write( "Question 530015: A person has two times as many nickels as quarters. If the total face value of these coins is $3.50, how many of each type of coin does this person have? \n" ); document.write( "

Algebra.Com's Answer #349855 by Edwin McCravy(20059) $\"\"$ $\"About$

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document.write( "The problem fails to state that the person has ONLY nickels and quarters.\r\n" );
document.write( "As the problem is stated she could have some other coins as well.  For \r\n" );
document.write( "instance, she could have 7 dimes, 8 quarters and 16 nickels, and she would\r\n" );
document.write( "still have $3.50 and twice as many nickels as quarters.  I just thought\r\n" );
document.write( "I would point that out as it might be interesting if you mentioned it to\r\n" );
document.write( "your teacher or classmates.  But I will assume that she has no other coins\r\n" );
document.write( "but nickels and quarters. \r\n" );
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document.write( "Assuming that she has ONLY nickels and quarters,\r\n" );
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document.write( "Let N = the number of quarters\r\n" );
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document.write( "Because of this statement:\r\n" );
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document.write( ">>...A person has two times as many nickels as quarters...<<\r\n" );
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document.write( "2N = the number of nickels.\r\n" );
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document.write( "To get our equation we use this principle:\r\n" );
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document.write( "    $.05 times  + $.25 times  = $3.50\r\n" );
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document.write( "                             .05(2N) + .25(N) = 3.50\r\n" );
document.write( "                               5(2N) +  25(N) = 350\r\n" );
document.write( "                                    10N + 25N = 350\r\n" );
document.write( "                                          35N = 350 \r\n" );
document.write( "                                            N = 10\r\n" );
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document.write( "So she has N = 10 quarters and 2N = 2(10) = 20 nickels.\r\n" );
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document.write( "Edwin

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