document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=530017>Question 530017</A>: <I><SPAN STYLE=\"word-break: break-all;\"> One number is 2 more than 5 times another. Their product is 39. Find the numbers. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #349852 by </B><A HREF=/tutors/aboutme.mpl?userid=algebrahouse.com><B>algebrahouse.com(1659)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=algebrahouse.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=algebrahouse.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=349852\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> \"One number is 2 more than 5 times another. Their product is 39. Find the numbers.\"\r<BR>\n" );
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document.write( "x = one number<BR>\n" );
document.write( "5x + 2 = other number\r<BR>\n" );
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document.write( "x(5x + 2) = 39 {their product is 39}<BR>\n" );
document.write( "5x^2 + 2x = 39 {used distributive property}<BR>\n" );
document.write( "5x^2 + 2x - 39 = 0 {subtracted 39 from both sides}<BR>\n" );
document.write( "(5x - 13)(x + 3) = 0 {factored into two binomials}<BR>\n" );
document.write( "5x - 13 = 0 or x + 3 = 0 {set each factor equal to 0}<BR>\n" );
document.write( "5x = 13 or x = -3 {added 13 and subtracted 3, respectively}<BR>\n" );
document.write( "x = 13/5 or x = -3 {divided first equation by 5}<BR>\n" );
document.write( "5x + 2 = 15 or 5x + 2 = -13 {substituted 13/5 and -3, in for x}\r<BR>\n" );
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document.write( "The numbers are:<BR>\n" );
document.write( "13/5 and 15<BR>\n" );
document.write( "and <BR>\n" );
document.write( "-3 and -13\r<BR>\n" );
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