document.write( "Question 529979: three fourths of a number increased by 32 is no more than 58. i cant figure it out please get back to me before 3:30 \n" ); document.write( "

Algebra.Com's Answer #349840 by KMST(5328) $\"\"$ $\"About$

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I believe they mean that after figuring out three fourth the number, then you increase that by 32. That would be, following tradition by calling the mistery number $\"x\"$ ,
\n" ); document.write( " $\"%283%2F4%29%2Ax%2B32\"$
\n" ); document.write( "If it's no more than 58, then it's less than or equal to 58, so
\n" ); document.write( " $\"%283%2F4%29%2Ax%2B32%3C=58\"$
\n" ); document.write( "You do the same operations to both sides, carefully undoing what has been done to $\"x\"$ .
\n" ); document.write( "First we subtract 32 (undoing the last thing done) to get
\n" ); document.write( " $\"%283%2F4%29%2Ax%3C=58-32\"$ or $\"%283%2F4%29%2Ax%3C=26\"$
\n" ); document.write( "Then we undo the three fourths calculation/multiplication by dividing by $\"3%2F4\"$ , which means mutiplying by $\"4%2F3\"$
\n" ); document.write( "to get
\n" ); document.write( " $\"x%3C=26%2A%284%2F3%29\"$ or $\"x%3C=104%2F3\"$ or $\"x%3C=34%2B%282%2F3%29\"$
\n" ); document.write( "CAUTION:
\n" ); document.write( "When multiplying/dividing both sides of an inequality by the same number, you have to be careful. If the number is negative, you have to flip < to > and viceversa. For example, it should be obvious that if
\n" ); document.write( " $\"x%3C0\"$ then multiplying both sides by $\"-1\"$
\n" ); document.write( "it makes sense to get $\"-x%3E0\"$ . \n" ); document.write( "

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