document.write( "Question 52450: A jar contains 40 coins consisting of dimes and quarters and having a total value of $4.90. How many of each kind of coin are there? \n" ); document.write( "
Algebra.Com's Answer #34984 by funmath(2933)![]() ![]() ![]() You can put this solution on YOUR website! Let the amount of dimes that you have=d \n" ); document.write( "Because the rest of the coins are quarters, let the amount of quarters you have=40-d. \n" ); document.write( "These are usually easier to solve in terms of cents instead of dollars to eliminate the decimals. \n" ); document.write( "Quarters are worth 25 cents, so the amount of money in quarters that you have is 25(40-d) \n" ); document.write( "Dimes are worth 10 cents, so the amount of money you have in dimes is 10d \n" ); document.write( "The total amount of money you have is 490 cents. \n" ); document.write( "25(40-d)+10d=490 \n" ); document.write( "1000-25d+10d=490 Don't forget to distribute the 25 to the d. \n" ); document.write( "1000+(-25+10)d=490 \n" ); document.write( "1000-15d=490 \n" ); document.write( "-1000+1000-15d=-1000+490 \n" ); document.write( "-15d=-510 \n" ); document.write( "-15d/-15=-510/-15 \n" ); document.write( "d=34 \n" ); document.write( "The amount of dimes is 34. \n" ); document.write( "The amount of quarters is 40-34=6 \n" ); document.write( " |