document.write( "Question 52450: A jar contains 40 coins consisting of dimes and quarters and having a total value of $4.90. How many of each kind of coin are there? \n" ); document.write( "
Algebra.Com's Answer #34984 by funmath(2933)\"\" \"About 
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Let the amount of dimes that you have=d
\n" ); document.write( "Because the rest of the coins are quarters, let the amount of quarters you have=40-d.
\n" ); document.write( "These are usually easier to solve in terms of cents instead of dollars to eliminate the decimals.
\n" ); document.write( "Quarters are worth 25 cents, so the amount of money in quarters that you have is 25(40-d)
\n" ); document.write( "Dimes are worth 10 cents, so the amount of money you have in dimes is 10d
\n" ); document.write( "The total amount of money you have is 490 cents.
\n" ); document.write( "25(40-d)+10d=490
\n" ); document.write( "1000-25d+10d=490 Don't forget to distribute the 25 to the d.
\n" ); document.write( "1000+(-25+10)d=490
\n" ); document.write( "1000-15d=490
\n" ); document.write( "-1000+1000-15d=-1000+490
\n" ); document.write( "-15d=-510
\n" ); document.write( "-15d/-15=-510/-15
\n" ); document.write( "d=34
\n" ); document.write( "The amount of dimes is 34.
\n" ); document.write( "The amount of quarters is 40-34=6
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