document.write( "Question 529840: how would i find the real solution to the equation: $\"+x%5E4%2B2x%5E2-1=0\"$ i know I'm suppose to put it in my calculator under the \"y=\" button and hit graph and find a point where the graph is crossed over the x-int, however i could be wrong. \n" ); document.write( "

Algebra.Com's Answer #349838 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

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how would i find the real solution to the equation: $\"+x%5E4%2B2x%5E2-1+=+0\"$
\n" ); document.write( "once you see the graph which should look like this
\n" ); document.write( " $\"+graph%28+300%2C+200%2C+-6%2C+6%2C+-6%2C+6%2C+x%5E4%2B2x%5E2-1%29+\"$
\n" ); document.write( "go to \"calc\" (2nd+trace)
\n" ); document.write( "use the down arrow to select \"Zero\" enter, it will return to the graph
\n" ); document.write( "It says, \"left bound\" you will see a * which you can move with the left and right arrows.
\n" ); document.write( "move to the left so it is above 0 on y axis, hit enter, it will say \"right bound\"
\n" ); document.write( "move the * to the right so it is below 0 on the y axis, hit enter, it will say \"guess\". Hit enter again
\n" ); document.write( "It will give you the x intercept (y=0) which is one solution, x=-.06435, do the same on the other cross over to get the other x intercept, x=+.6435 y=0
\n" ); document.write( ":
\n" ); document.write( "You can find all real solutions using this. \r
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