document.write( "Question 529236: 78+3c+12-c+4, 1+p+5+p=2 please explain clearly and show the steps \n" ); document.write( "

Algebra.Com's Answer #349808 by boilpoil(127) $\"\"$ $\"About$

You can put this solution on YOUR website!
I think you wish to simplify the first one and solve the second one.\r
\n" ); document.write( "\n" ); document.write( "1)
\n" ); document.write( "78+3c+12-c+4
\n" ); document.write( "78+12+4+3c-c --- Reordering the terms: Numbers with numbers, unknowns with unknowns
\n" ); document.write( "94+2c --- Calculating: 78+12+4 = 94, 3c-(1)c = 2c\r
\n" ); document.write( "\n" ); document.write( "This would be your final answer\r
\n" ); document.write( "\n" ); document.write( "2)
\n" ); document.write( "1+p+5+p=2
\n" ); document.write( "1+5+p+p=2 --- Reordering the terms: Numbers with numbers, unknowns with unknowns
\n" ); document.write( "6+2p=2 --- Calculating: 1+5=6, p+p=2p
\n" ); document.write( "2p=2-6 --- Moved the term +6 to the right hand side and becomes -6
\n" ); document.write( "2p=-4 --- Calculating: 2-6 = -4
\n" ); document.write( " $\"2p%2F2=-4%2F2\"$ --- Dividing both sides by 2, and erases the denominator of '2p'
\n" ); document.write( "p=-2 \n" ); document.write( "

\n" );