document.write( "Question 528917: Please help me!\r
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document.write( "I need to graph this and I have no idea how to do it.
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document.write( "x^2 -x-5 = 0 I need at least 4 points,\r
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document.write( "Thank you so much! \n" );
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Algebra.Com's Answer #349792 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! I need to graph this and I have no idea how to do it. \n" ); document.write( "x^2 -x-5 = 0 I need at least 4 points, \n" ); document.write( "** \n" ); document.write( "Like all 2nd degree equations, curve will be that of a parabola. \n" ); document.write( "Rewrite equation: \n" ); document.write( "y=x^2-x-5 \n" ); document.write( "y-intercept: \n" ); document.write( "set x=0, then solve for y \n" ); document.write( "y=-5 \n" ); document.write( ".. \n" ); document.write( "complete the square \n" ); document.write( "y=(x^2-x+.25)-5-.25 \n" ); document.write( "y=(x-.5)^2-5.25 \n" ); document.write( "This is an equation for a parabola of the standard form: y=(x-h)^2+k, with (h,k) being the (x,y) coordinates of the vertex. \n" ); document.write( "vertex(0.5,-5.25) \n" ); document.write( ".. \n" ); document.write( "x-intercepts \n" ); document.write( "set y=0 \n" ); document.write( "(x-.5)^2-5.25=0 \n" ); document.write( "(x-.5)^2=5.25 \n" ); document.write( "take sqrt of both sides \n" ); document.write( "x-.5=±√(5.25)≈±2.3 \n" ); document.write( "x≈.5±2.3 \n" ); document.write( "x≈2.8 \n" ); document.write( "or \n" ); document.write( "x≈-1.8 \n" ); document.write( "You now have the following 4 points with which you can graph the given function: \n" ); document.write( "(0,-5) y-intercept \n" ); document.write( "(0.5,-5.25) vertex \n" ); document.write( "(2.8,0) x-intercept \n" ); document.write( "(-1.8,0) x-intercept \n" ); document.write( " |