document.write( "Question 529922: A car and bus leave at the same time and travel to the same place. The car travels 21 mph faster than the bus and gets there in four hours. The bus gets there two hours later. Find the speed of the bus and car. \n" ); document.write( "
Algebra.Com's Answer #349784 by boilpoil(127)\"\" \"About 
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We could try using algebra:\r
\n" ); document.write( "\n" ); document.write( "Let the speed of car be x
\n" ); document.write( "Then the speed of bus is x-21\r
\n" ); document.write( "\n" ); document.write( "\"4x=6%28x-21%29\" ---The speed of the car is x, it traveled 4 hours, so 4x represents the total distance, the bus uses 6 hours with a speed of x-21 so it also represents the distance
\n" ); document.write( "\"4x=6x-126\"
\n" ); document.write( "\"-2x=-126\"
\n" ); document.write( "\"x=63%28mph%29\"\r
\n" ); document.write( "\n" ); document.write( " The speed of bus
\n" ); document.write( "=63-21
\n" ); document.write( "=42(mph)\r
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