document.write( "Question 529835: A tank contains 20 gallons of antifreeze solution. When it is full, it contains 15% antifreeze. How many gallons must be replaced by an 80% antifreeze solution to get 20 gallons of a 70% solution? \n" ); document.write( "
Algebra.Com's Answer #349769 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
Let \"x\" = gallons of 15% antifreeze to be
\n" ); document.write( "removed and replaced with 80% antifreeze
\n" ); document.write( "In words:
\n" ); document.write( "( gallons of pure antifreeze at end)/( gallons of solution at end) = 70%
\n" ); document.write( "-------------
\n" ); document.write( "\"+.15%2A20+=+3+\" gallons of pure antifreeze at start
\n" ); document.write( "\"+20+-+x+\" gallons of solution left after removal of \"x\" gallons
\n" ); document.write( "\"+.15%2A%28+20+-+x+%29+\" = pure antifreeze left after removal of \"x\" gallons
\n" ); document.write( "\"+.8x+\" = pure antifreeze in 80% solution added
\n" ); document.write( "The total gallons of solution has not changed
\n" ); document.write( "\"+%28+.8x+%2B+.15%2A%28+20+-+x+%29+%29+%2F+20+=+.7+\"
\n" ); document.write( "\"+.8x+%2B+3+-+.15x+=+14+\"
\n" ); document.write( "\"+.65x+=+11+\"
\n" ); document.write( "\"+x+=+16.923+\"
\n" ); document.write( "16.923 gallons must be removed and replace with
\n" ); document.write( "16.923 gallons of 80% antifreeze
\n" ); document.write( "-----------
\n" ); document.write( "check:
\n" ); document.write( "\"+20+-+16.923+=+3.077+\" gallons of solution left after removal of \"x\" gallons
\n" ); document.write( "\"+.15%2A%28+20+-+16.923+%29+=+.4615+\" = pure antifreeze left after removal of \"x\" gallons
\n" ); document.write( "\"+.8%2A16.923+=+13.538+\" = pure antifreeze in 80% solution added
\n" ); document.write( "\"+%28+.8x+%2B+.15%2A%28+20+-+x+%29+%29+%2F+20+=+.7+\"
\n" ); document.write( "\"+%28+13.538+%2B+.4615+%29+%2F+20+=+.7+\"
\n" ); document.write( "\"+13.9995+%2F+20+=+.7+\"
\n" ); document.write( "\"+13.9995+=+14+\"
\n" ); document.write( "error due to rounding off- OK\r
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