document.write( "Question 529579: If Steven can mix 20 drinks in 5 minutes, Sue can mix 20 drinks in 10 minutes, and Jack can mix 20 drinks in 15 minutes, how much time will it take all 3 of them working together to mix the 20 drinks? \n" ); document.write( "
Algebra.Com's Answer #349768 by ankor@dixie-net.com(22740)\"\" \"About 
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If Steven can mix 20 drinks in 5 minutes,
\n" ); document.write( " Sue can mix 20 drinks in 10 minutes,
\n" ); document.write( "and Jack can mix 20 drinks in 15 minutes,
\n" ); document.write( "ow much time will it take all 3 of them working together to mix the 20 drinks?
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\n" ); document.write( "There is an easy way to do this.
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\n" ); document.write( "Let t = time required to do the job when they all work together
\n" ); document.write( "Let the completed job = 1 (the mixing of 20 drinks)
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\n" ); document.write( "\"t%2F5\" + \"t%2F10\" + \"t%2F15\" = 1
\n" ); document.write( "multiply by 30, the LCM of the 3 denominators
\n" ); document.write( "30*\"t%2F5\" + 30\"t%2F10\" + 30*\"t%2F15\" = 30(1)
\n" ); document.write( "Cancel out the denominators and you have
\n" ); document.write( "6t + 3t + 2t = 30
\n" ); document.write( "11t = 30
\n" ); document.write( "t = \"30%2F11\"
\n" ); document.write( "t = 2.73 minutes or 2 + .73(60) = 2 min 43.6 seconds
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\n" ); document.write( "Check this
\n" ); document.write( "\"2.73%2F5\" + \"2.73%2F10\" + \"2.73%2F15\" =
\n" ); document.write( ".546 + .273 + .182 = 1.00; confirms our solution of 2.73 min
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