document.write( "Question 529579: If Steven can mix 20 drinks in 5 minutes, Sue can mix 20 drinks in 10 minutes, and Jack can mix 20 drinks in 15 minutes, how much time will it take all 3 of them working together to mix the 20 drinks? \n" ); document.write( "
Algebra.Com's Answer #349768 by ankor@dixie-net.com(22740) You can put this solution on YOUR website! If Steven can mix 20 drinks in 5 minutes, \n" ); document.write( " Sue can mix 20 drinks in 10 minutes, \n" ); document.write( "and Jack can mix 20 drinks in 15 minutes, \n" ); document.write( "ow much time will it take all 3 of them working together to mix the 20 drinks? \n" ); document.write( ": \n" ); document.write( "There is an easy way to do this. \n" ); document.write( ": \n" ); document.write( "Let t = time required to do the job when they all work together \n" ); document.write( "Let the completed job = 1 (the mixing of 20 drinks) \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( "multiply by 30, the LCM of the 3 denominators \n" ); document.write( "30* \n" ); document.write( "Cancel out the denominators and you have \n" ); document.write( "6t + 3t + 2t = 30 \n" ); document.write( "11t = 30 \n" ); document.write( "t = \n" ); document.write( "t = 2.73 minutes or 2 + .73(60) = 2 min 43.6 seconds \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check this \n" ); document.write( " \n" ); document.write( ".546 + .273 + .182 = 1.00; confirms our solution of 2.73 min \n" ); document.write( " |