document.write( "Question 529831: At a party there are two types of appetizers: A and B. The probability that a person chooses A is 0.3 while the probability that the person chooses B is 0.4. The probability that the person chooses both is 0.25. What is the probability that a person does not choose any appetizer? \n" ); document.write( "
Algebra.Com's Answer #349763 by swincher4391(1107)\"\" \"About 
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We know that P(A,B,AandB,not(A or B)) = 1. In other words, the probability of atleast one of all possible events happening is 1.\r
\n" ); document.write( "\n" ); document.write( "So the probability of three of those events is 0.3 + 0.4 + 0.25 as given.\r
\n" ); document.write( "\n" ); document.write( "So we have 0.95. Then 1 - 0.95 is the probability of neither happening. \r
\n" ); document.write( "\n" ); document.write( "So it is 0.05.
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