document.write( "Question 529802: Please help with this question. My son needs help. Thank you so much!\r
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\n" ); document.write( "Two rectangles are similar. One is 5 cm by 12 cm. the longer side of the second rectangle is 8 cm greater than twice the shorter side. find its length and width.\r
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Algebra.Com's Answer #349731 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
5/12 = x/(2x+8)\r
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\n" ); document.write( "\n" ); document.write( "5(2x+8) = 12x\r
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\n" ); document.write( "\n" ); document.write( "10x+40=12x\r
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\n" ); document.write( "\n" ); document.write( "10x=12x-40\r
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\n" ); document.write( "\n" ); document.write( "10x-12x=-40\r
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\n" ); document.write( "\n" ); document.write( "-2x=-40\r
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\n" ); document.write( "\n" ); document.write( "x=(-40)/(-2)\r
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\n" ); document.write( "\n" ); document.write( "x=20\r
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\n" ); document.write( "\n" ); document.write( "So the shorter side is 20 cm and the longer side is 2*20 + 8 = 48 cm
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