document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=529799>Question 529799</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle exceeds the width by 2cm. If the diagonal is 10cm long, find the width of the rectangle.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #349727 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=349727\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> L^2 + W^2 = D^2\r<BR>\n" );
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document.write( "(W+2)^2 + W^2 = 10^2\r<BR>\n" );
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document.write( "W^2 + 4W + 4 + W^2 = 100\r<BR>\n" );
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document.write( "W^2 + 4W + 4 + W^2 - 100 = 0\r<BR>\n" );
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document.write( "2W^2 + 4W - 96 = 0\r<BR>\n" );
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document.write( "2(W^2 + 2W - 48) = 0\r<BR>\n" );
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document.write( "2(W + 8)(W - 6) = 0\r<BR>\n" );
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document.write( "W + 8 = 0 or W - 6 = 0\r<BR>\n" );
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document.write( "W = -8 or W = 6\r<BR>\n" );
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document.write( "Throw out the negative solution to get W = 6\r<BR>\n" );
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document.write( "So the width is 6 cm and the length is 6+2 = 8 cm\r<BR>\n" );
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document.write( "Jim </SPAN>\n" );
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