document.write( "Question 529769: The sum of the squares of two integers is 80 and one number is twice the other. What are the numbers? \n" ); document.write( "
Algebra.Com's Answer #349722 by swincher4391(1107)\"\" \"About 
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x^2 + y^2 = 80
\n" ); document.write( "x = 2y\r
\n" ); document.write( "\n" ); document.write( "(2y)^2 + y^2 = 80
\n" ); document.write( "4y^2 + y^2 = 80
\n" ); document.write( "5y^2 = 80
\n" ); document.write( "y^2 = 16
\n" ); document.write( "y=4 [or -4]\r
\n" ); document.write( "\n" ); document.write( "So x = 2(4)\r
\n" ); document.write( "\n" ); document.write( "x = 8 [or -8]\r
\n" ); document.write( "\n" ); document.write( "4 and 8 are your answers. But if you think about it, -4 and -8 work too. Not sure how advanced your class is, but yeah, think about it. -4^2 + -8^2 = 16 + 64 = 80 and -4 * 2 = -8.
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