document.write( "Question 529700: Two numbers, which differ by 3, have a product of 88. Find them. \n" ); document.write( "

Algebra.Com's Answer #349673 by unlockmath(1688) $\"\"$ $\"About$

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Hello,
\n" ); document.write( "Let's set up one number as n and the other as n+3, now we can write an equation as:
\n" ); document.write( "n(n+3)=88
\n" ); document.write( "Expand this:
\n" ); document.write( "n^2+3n=88
\n" ); document.write( "Subtract 88:
\n" ); document.write( "n^2+3n-88=0
\n" ); document.write( "Factor:
\n" ); document.write( "(n-8)(n+11)=0
\n" ); document.write( "Solve for n:
\n" ); document.write( "n = 8
\n" ); document.write( "n= -11
\n" ); document.write( "From this we see that 8 times 11
\n" ); document.write( "or -11 times -8 works.
\n" ); document.write( "Make sense?
\n" ); document.write( "RJ
\n" ); document.write( "www.math-unlock.com \n" ); document.write( "

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