document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=529655>Question 529655</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hello, at first we have the complex number z = -1 + i sqrt(3). <BR>\n" );
document.write( "Secondly we have the fraction z/(1 + 2i).<BR>\n" );
document.write( "If we substitute z in the numerator we get: {(-1 + i sqrt(3)}/(1+2i). <BR>\n" );
document.write( "How do we calculate this fraction into the form a + bi, (a,b belong to R)?\r<BR>\n" );
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document.write( "Thanks a lot in advance </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #349660 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=349660\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> clear the complex number from the denominator by FOILing the numerator AND denominator with the conjugate, (1 - 2i)\r<BR>\n" );
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document.write( "remember, i^2 is -1 </SPAN>\n" );
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