document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=529629>Question 529629</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do I solve this system of linear equations? This is the problem: x-4=y, y/2 plus 5=2x   Just to let you know I need a high level of explanation, or a lot of detail in your explanation. Please dont assume I know a lot about this subject. THANKS!!!  Crystal </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #349658 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=349658\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> multiplying by 2 to clear the fraction from the 2nd eqn ___ y + 10 = 4x (all the terns are multiplied)\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "subtracting 10 to find y ___ y = 4x - 10\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "you now have an equivalent value for y that you can SUBSTITUTE into the 1st eqn\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "x - 4 = 4x - 10 ___ subtracting x and adding 10 ___ 6 = 3x\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "solve for x and substitute the value into any of the eqns to find y </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );