document.write( "Question 529505: I need help!\r
\n" ); document.write( "\n" ); document.write( "A person travels 15 miles in 1/3 of an hour, then returns by traveling that same 15 miles in 1/7 of an hour. What is that person's average rate for the trip?\r
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Algebra.Com's Answer #349657 by MathTherapy(10555)\"\" \"About 
You can put this solution on YOUR website!
I need help!\r
\n" ); document.write( "\n" ); document.write( "A person travels 15 miles in 1/3 of an hour, then returns by traveling that same 15 miles in 1/7 of an hour. What is that person's average rate for the trip?\r
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\n" ); document.write( "\n" ); document.write( "Average rate = total distance, divided by total time\r
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\n" ); document.write( "\n" ); document.write( "We then have: \"%2815+%2B+15%29%2F%28%281%2F3%29+%2B+%281%2F7%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"30%2F%2810%2F21%29\", or \"30%2821%2F10%29\", or \"highlight_green%2863%29\" mph\r
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\n" ); document.write( "\n" ); document.write( "Send comments and “thank-yous” to “D” at MathMadEzy@aol.com
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