document.write( "Question 529505: I need help!\r
\n" ); document.write( "\n" ); document.write( "A person travels 15 miles in 1/3 of an hour, then returns by traveling that same 15 miles in 1/7 of an hour. What is that person's average rate for the trip?\r
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Algebra.Com's Answer #349641 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
A person travels 15 miles in 1/3 of an hour, then returns by traveling that same 15 miles in 1/7 of an hour.
\n" ); document.write( " What is that person's average rate for the trip?
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\n" ); document.write( "Let a = the average speed of the 30 mi trip
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\n" ); document.write( "Write a time equation, time = dist/speed
\n" ); document.write( "\"15%2F%281%2F3%29\" + \"15%2F%281%2F7%29\" = \"30%2Fa\"
\n" ); document.write( "invert the dividing fraction and multiply
\n" ); document.write( "3(15) + 7(15) = \"30%2Fa\"
\n" ); document.write( "45 + 105 = \"30%2Fa\"
\n" ); document.write( "150 = \"30%2Fa\"
\n" ); document.write( "Multiply both sides by a
\n" ); document.write( "150a = 30
\n" ); document.write( "divide both sides by 150
\n" ); document.write( "a = \"30%2F150\"
\n" ); document.write( "a = \"1%2F5\" mph hr is the average speed
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