document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=529602>Question 529602</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If two cards are drawn from a standard 52 card deck without replacement, in how many different ways is it possible to obtain a heart on the first draw and an ace on the second? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #349640 by </B><A HREF=/tutors/aboutme.mpl?userid=josmiceli><B>josmiceli(19441)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josmiceli><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=josmiceli><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=349640\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I'd get a 2nd opinion on this, but here's my view:<BR>\n" );
document.write( "There are 13 ways that you can draw a heart first<BR>\n" );
document.write( "Having drawn the heart, there are 4 ways to draw<BR>\n" );
document.write( "an ace, so there are <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+13%2A4+=+52+ ALIGN=MIDDLE  ALT=\"+13%2A4+=+52+\"   DISABLED_style= \"max-width:90%; height:auto;\" > ways to get<BR>\n" );
document.write( "this combination. But what if the 1st card is the<BR>\n" );
document.write( "Ace of hearts. Then there are only 3 ways to draw<BR>\n" );
document.write( "an Ace. So I have to subtract the one combination<BR>\n" );
document.write( "that I counted twice, that is Ace of hearts and<BR>\n" );
document.write( "Ace of hearts again.<BR>\n" );
document.write( "There are then 51 ways to draw a heart and then<BR>\n" );
document.write( "an Ace. Hope I got it. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );