document.write( "Question 529535: I could use some help with this problem please.Determine f^-1 for
\n" ); document.write( " f(x)=∛(x+5. It's cubed if it is too small to see. Thank you
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Algebra.Com's Answer #349616 by MathLover1(20849)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "\"f%5E%28-1%29%28x%29+=+root%283%2C+%28x%2B5%29%29+\" you refer to the inverse of the function f(x). \r
\n" ); document.write( "\n" ); document.write( "Given \"y+=+root%283%2C+%28x%2B5%29%29\"
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\n" ); document.write( "to find an inverse of f(x) you will need interchange the \"x\" and \"y\": \r
\n" ); document.write( "\n" ); document.write( "\"x+=+root%283%2C+%28y%2B5%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "now solve for \"y\":\r
\n" ); document.write( "\n" ); document.write( "To undo the cube root, you must cube both sides:\r
\n" ); document.write( "\n" ); document.write( "\"x+=+%28root%283%2C+%28y%2B5%29%29%29%5E3\"\r
\n" ); document.write( "\n" ); document.write( "\"x%5E3+=+y%2B5+\"\r
\n" ); document.write( "\n" ); document.write( "\"x%5E3+-+5+=+y\"\r
\n" ); document.write( "\n" ); document.write( "or
\n" ); document.write( "\"y=x%5E3+-+5+\"\r
\n" ); document.write( "\n" ); document.write( "This new \"y+\" that you just solved for the the inverse function for \"f%28x%29\"; so, the inverse function for \"f%28x%29+=root%283%2C+%28y%2B5%29%29+\" is \"f%5E%28-1%29+%28x%29+=+x%5E3+-+5+\"\r
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