document.write( "Question 529388: A hiker traveled at an average rate of 2 kilometers per hour (km/h) going up to a lookout and traveled at an average rate of 5 km/h coming back down. If the entire trip (not counting a lunch stop at the lookout) took approximately 2 hours and 15 minutes, what is the total distance the hiker walked? Round your answer to the nearest tenth of a kilometer. \n" ); document.write( "
Algebra.Com's Answer #349614 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! A hiker traveled at an average rate of 2 kilometers per hour (km/h) going up to a lookout and traveled at an average rate of 5 km/h coming back down. \n" ); document.write( " If the entire trip (not counting a lunch stop at the lookout) took approximately 2 hours and 15 minutes, what is the total distance the hiker walked? \n" ); document.write( " Round your answer to the nearest tenth of a kilometer. \n" ); document.write( ": \n" ); document.write( "Let d = the one-way distance \n" ); document.write( ": \n" ); document.write( "Write a time equation, time = dist/speed, change 2 hr 15 min to 2.25 hrs \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( "multiply by 10 to clear the denominators, results: \n" ); document.write( "5d + 2d = 10(2.25) \n" ); document.write( "7d = 22.5 \n" ); document.write( "d = \n" ); document.write( "d = 3.214 one way, 2(2.214) = 6.43 ~ 6.4 km, total distance \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check solution find the actual times \n" ); document.write( "3.2/2 = 1.6 \n" ); document.write( "3.2/5 = .64 \n" ); document.write( "----------- \n" ); document.write( "total time: 2.24 ~ 2.25, confirms our solution \n" ); document.write( " |