document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=52415>Question 52415</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I am having a problem with 11/14 over 4 - 6/7. I know to use the Order of Operations: Parenthesis, Exponents, Multiplication, Division, Addition and Subtraction. Sometimes, I become stymied with some of the problems. Our professor doesn't explain the actual mechanics of a problem. I haven't been in school in 42 years.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #34960 by </B><A HREF=/tutors/aboutme.mpl?userid=rapaljer><B>rapaljer(4671)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rapaljer><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rapaljer><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=34960\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I would suggest that you start by calculating 4-6/7 by finding a common denominator which is 7.  This would be 28/7 - 6/7 = 22/7.\r<BR>\n" );
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document.write( "Now, find 11/14 divided by 22/7 by inverting the second number and multiplying.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+%2811%2F14%29%2A%28+7%2F22%29+ ALIGN=MIDDLE  ALT=\"+%2811%2F14%29%2A%28+7%2F22%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Divide out the 11 into 22 which goes 2 times, and divide out the 7 into the 14 which also goes 2 times, and what is left is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=1%2F4 ALIGN=MIDDLE  ALT=\"1%2F4\"   DISABLED_style= \"max-width:90%; height:auto;\" >.\r<BR>\n" );
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document.write( "R^2 at SCC<BR>\n" );
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