document.write( "Question 529386: A father is 26years older than his daughter. In 4years he will be 2 more than 5x her age. What are their current ages?
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Algebra.Com's Answer #349578 by Maths68(1474)![]() ![]() You can put this solution on YOUR website! Let \n" ); document.write( "Present age of father = f \n" ); document.write( "Present age of daughter = d\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "A father is 26years older than his daughter. \n" ); document.write( "f=d+26...........(1)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "In 4 years \n" ); document.write( "Father will be = f+4 \n" ); document.write( "Daughter will be = d+4\r \n" ); document.write( "\n" ); document.write( "Then\r \n" ); document.write( "\n" ); document.write( "father will be 2 more than 5 times of her age. \n" ); document.write( "f+4=5(d+4)+2 \n" ); document.write( "f+4=5d+20+2 \n" ); document.write( "f+4=5d+22 \n" ); document.write( "f=5d+22-4 \n" ); document.write( "f=5d+18.................(2) \n" ); document.write( "Put the value of f from (1) to (2) \n" ); document.write( "d+26=5d+18 \n" ); document.write( "d-5d=18-26 \n" ); document.write( "-4d=-8 \n" ); document.write( "Divide by -4 both sides \n" ); document.write( "-4d/-4=-8/-4 \n" ); document.write( "d=2 \n" ); document.write( "Put the value of d in (1) \n" ); document.write( "f=d+26 \n" ); document.write( "f=2+26 \n" ); document.write( "f=28\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Present age of father = f = 28 years old \n" ); document.write( "Present age of daughter = d = 2 years old \n" ); document.write( " \n" ); document.write( " |