document.write( "Question 529386: A father is 26years older than his daughter. In 4years he will be 2 more than 5x her age. What are their current ages?
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Algebra.Com's Answer #349578 by Maths68(1474)\"\" \"About 
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Let
\n" ); document.write( "Present age of father = f
\n" ); document.write( "Present age of daughter = d\r
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\n" ); document.write( "\n" ); document.write( "A father is 26years older than his daughter.
\n" ); document.write( "f=d+26...........(1)\r
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\n" ); document.write( "\n" ); document.write( "In 4 years
\n" ); document.write( "Father will be = f+4
\n" ); document.write( "Daughter will be = d+4\r
\n" ); document.write( "\n" ); document.write( "Then\r
\n" ); document.write( "\n" ); document.write( "father will be 2 more than 5 times of her age.
\n" ); document.write( "f+4=5(d+4)+2
\n" ); document.write( "f+4=5d+20+2
\n" ); document.write( "f+4=5d+22
\n" ); document.write( "f=5d+22-4
\n" ); document.write( "f=5d+18.................(2)
\n" ); document.write( "Put the value of f from (1) to (2)
\n" ); document.write( "d+26=5d+18
\n" ); document.write( "d-5d=18-26
\n" ); document.write( "-4d=-8
\n" ); document.write( "Divide by -4 both sides
\n" ); document.write( "-4d/-4=-8/-4
\n" ); document.write( "d=2
\n" ); document.write( "Put the value of d in (1)
\n" ); document.write( "f=d+26
\n" ); document.write( "f=2+26
\n" ); document.write( "f=28\r
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\n" ); document.write( "\n" ); document.write( "Present age of father = f = 28 years old
\n" ); document.write( "Present age of daughter = d = 2 years old
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