document.write( "Question 529334: Mrs Sabado is 6 times as old as her daughter May. Next year her age will be equal to the square of her daughter's age. Find the present age. \n" ); document.write( "
Algebra.Com's Answer #349551 by oberobic(2304)\"\" \"About 
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x = Mrs. Sabado's age
\n" ); document.write( "d = her daughter's age
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\n" ); document.write( "x = 6d
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\n" ); document.write( "next year
\n" ); document.write( "x+1 = (d+1)^2
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\n" ); document.write( "substitute
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\n" ); document.write( "6d+1 = d^2 + 2d + 1
\n" ); document.write( "d^2 -4d = 0
\n" ); document.write( "d(d-4) = 0
\n" ); document.write( "d = 0 or 4
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\n" ); document.write( "d = 4 = daughter's age
\n" ); document.write( "x = 24 = Mrs. Sabado's age
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\n" ); document.write( "Check for next year.
\n" ); document.write( "d = 4+1 = 5
\n" ); document.write( "d^2 = 25
\n" ); document.write( "Which is how old Mrs. Sabado will be.
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\n" ); document.write( "Answer: Mrs. Sabado is 24 and her daughter is 4.
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\n" ); document.write( "Done.
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