document.write( "Question 529309: Need assistance with this, i cant figure it out. It's driving me mad. Thank you.\r
\n" ); document.write( "\n" ); document.write( "Lena is choosing between two exercise routines.\r
\n" ); document.write( "\n" ); document.write( "In routine #1, she burns 25 calories walking. She then runs at a rate that burns 18 calories per minute.\r
\n" ); document.write( "\n" ); document.write( "In routine #2, she burns 49 calories walking. She then runs at a rate that burns 14 calories per 
\n" ); document.write( "minute.\r
\n" ); document.write( "\n" ); document.write( "For what amount of time spent running will routine #1 burn fewer calories than routine#2? Use t for the number of minutes spent running, and solve your inequality for t.
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Algebra.Com's Answer #349543 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
Let \"t\" = minutes spent running
\n" ); document.write( "given:
\n" ); document.write( "Routine #1
\n" ); document.write( "Calories burnt = \"+25+%2B+18t+\"
\n" ); document.write( "Routine #2
\n" ); document.write( "Calories burnt = \"+49+%2B+14t+\"
\n" ); document.write( "------------------------
\n" ); document.write( "Let calories burnt = \"C\"
\n" ); document.write( "The question is:
\n" ); document.write( "for what values of \"t\" is
\n" ); document.write( "\"+49+%2B+14t+%3E+25+%2B+18t+\"
\n" ); document.write( "Subtract \"+14t+\" from both sides
\n" ); document.write( "\"+49+%3E+25+%2B+4t+\"
\n" ); document.write( "Subtract \"+25\" from both sides
\n" ); document.write( "\"+24+%3E+4t+\"
\n" ); document.write( "\"+6+%3E+t+\"
\n" ); document.write( "or, what is the same,
\n" ); document.write( "\"+t+%3C+6+\"
\n" ); document.write( "So, for all values of \"t+%3C+6+\" minutes spent running,
\n" ); document.write( "The calories burnt using routine #1 are less than
\n" ); document.write( "the calories burnt using #2
\n" ); document.write( "Here's a plot of routine #1 and #2:
\n" ); document.write( "\"+graph%28+400%2C+400%2C+-1%2C+7%2C+-5%2C+150%2C+18x+%2B+25%2C+14x+%2B+49+%29+\"
\n" ); document.write( "The bottom line is routine #1. You can see that when \"+t+=+0+\"
\n" ); document.write( "\"+C+=+25+\" as it should, and they meet at \"t=6\"
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