document.write( "Question 529189: a plane took 4 h to fly 2200 km from saskatoon to toronto with a tail wind.The return trip,with a head wind,took 5 h.Find the speed of the plane in still air and the wind speed \n" ); document.write( "
Algebra.Com's Answer #349537 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! a plane took 4 h to fly 2200 km from saskatoon to toronto with a tail wind. \n" ); document.write( "The return trip,with a head wind,took 5 h. \n" ); document.write( "Find the speed of the plane in still air and the wind speed \n" ); document.write( ": \n" ); document.write( "Let s = the speed of the plane \n" ); document.write( "Let w = speed of the wind \n" ); document.write( "then \n" ); document.write( "(s+w) = effective speed with the wind \n" ); document.write( "and \n" ); document.write( "(s-w) = effective speed against the wind \n" ); document.write( ": \n" ); document.write( "Write a distance equation for each trip, dist = speed * time \n" ); document.write( ": \n" ); document.write( "5(s-w) = 2200 \n" ); document.write( "4(s+w) = 2200 \n" ); document.write( "Simplify, divide the 1st equation by 5, the 2nd equation by 4, results \n" ); document.write( "s - w = 440 \n" ); document.write( "s + w = 550 \n" ); document.write( "-----------adding eliminates w, find s \n" ); document.write( "2s = 990 \n" ); document.write( "s = \n" ); document.write( "s = 495 mph is the speed of the plane \n" ); document.write( "and \n" ); document.write( "495 + w = 550 \n" ); document.write( "w = 550 - 495 \n" ); document.write( "w = 55 mph is speed of the wind \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check solution in the original 1st equation \n" ); document.write( "5(495 - 55) = \n" ); document.write( "5(440) = 2200 \n" ); document.write( " |